The gas sample has a volume of 51.0 μL at 22.0 °C. What is the volume of the gas after the sample is cooled to 9.6 °C at constant pressure?

Answer 1

Constant pressure = Charles Law:

V1/T1 = V2/T2

V1 = 51.0 ul

T1 = 22ºC + 273 = 295K

V2 = ?

T2 = 9.6ºC + 273 = 282.6K

Plug the values in and solve for V2

Answer 2

The pressure is constant so the ideal gas law can be rearranged from PV=nRT to V=(nR/P)T. (nR/P) is a constant so V=cT and as a result, V is now directly proportional to T. We can then use V₁/T₁ = V₂/T₂ and rearrange to solve for V₂=V₁T₂/T₁. You can now solve for V₂. Be sure to keep your units consistent.

I hope this helps!