A Mass of Al is Heated

Question

A 26.1 g mass of Al was heated to 100 Celsius and then plunged into 100 g of water at 24 Celsius. The temperature of the resulting mixture became 28.0 Celsius. What is the experimental specific heat capacity of aluminum?

Answer 1

Heat lost by Al = heat gained by water

mCΔT = mCΔT

(26.1g)(C)(28-100) = (100 g)(4.184 J/g/deg)(28-24)

Solve for C = specific heat of Al