J.R. S. answered 05/04/19
Ph.D. University Professor with 10+ years Tutoring Experience
w = -P∆V
where w = work; P = pressure; ∆V = change in volume
w = -(2.0 atm)(48 L - 92 L) = -2.0 atm x -44 L = + 88 L-atm = +88 joules
The work is done by the surroundings on the gas and so has a positive (+) sign. The magnitude of the work is 88 joules.