What is the axis of symmetry of this equation: y = -2x^2 + 6x + 7?

Answer 1

Symmetry, xs become negative.

f(-x)=-2*(-x)^2+6(-x)+7

-2x^2-6x+7

By looking at the calculator the axis is "x". The point centered is (-1.8,0). 2 ends of arch: (-24,-1)(24,-1.2).

Answer 2

y = -2x^2 + 6x + 7?

This is in standard form

y=Ax²+Bx+C

A=-2

B=6

C=7

The axis of symmetry equation is

X=-B/2A

X=-6/2(-2)

X=-6/-4

Reduce x=3/2