J.R. S. answered 05/03/19
Ph.D. University Professor with 10+ years Tutoring Experience
Chemists don't use N (normality) anymore, but in this problem, 2N is equivalent to 2 M because NaOH has one equivalent per mole. To prepare 2 N/2 M NaOH, we need 2 moles/liter of solution. For 1.5 liters, we need
2 moles/L x 1.5 liters = 3 moles NaOH
3 moles NaOH x 40 g/mole = 120 g NaOH required
40% w/v = 40 g NaOH/100 ml
40 g/100 ml (x ml) = 120 g and x = 300 mls of 40% w/v NaOH is required