Which has a greater area or rectangle with sides 16.8 cm and 14.4 CM or Rhombus with diagonals 30 cm 42 cm and by how much?

Answer 1

Area of a rectangle is length*width

The area of the rectangle is 16.8*14.4=241.92cm²

Area of a rhombus is (diagonal₁*diagona₂)/2

The reason for this is you can look at the diagonals creating 2 equal triangles in the rhombus, if you take only half of one of the diagonals. So in other words you would take half a diagonal and use the formula for a triangle then multiply it by 2 because there are two of them.

Well, by taking half of the diagonal then multiplying it by 2 later, that undoes itself. So instead just use the area of a triangle formula with the diagonals being the base and height.

The area of the rhombus is (42*30)/2=630cm²

Then subtract, 630-241.92=388.08cm²

The Rhombus is bigger by 388.08cm²