At what temperature in kelvin will 5.00 grams of CO2 exert a pressure of 4.65 atm at a volume of 0.250 liters? PLEASE SHOW WORK

Answer 1

Using the ideal gas law, PV = nRT and solving for T...

P = pressure = 4.65 atm

V = volume = 0.250 L

n = moles = 5.00 g CO2 x 1 mol/44 g = 0.1136 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K

PV = nRT

T = PV/nR = (4.65)(0.250)/(0.1136)(0.0821)

T = 125K