Calculate the volume of 16 grams of Sulfur Dioxide at STP

Answer 1

At STP 1 mole of an ideal gas = 22.4 L.

Assuming SO₂ (sulfur dioxide) acts as an ideal as, we have 16 g SO₂ x 1 mol/64 g = 0.25 moles SO₂

0.25 moles x 22.4 L/mole = 5.6 liters