Mark M. answered 05/02/19
Tutor
5.0
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Mathematics Teacher - NCLB Highly Qualified
m∠POR = 90º + (0.5)m∠PQR
115º = 90º + (0.5)m∠PQR
25º = (0.5)ºm∠PQR
50º = m∠PQR
Mark M. answered 05/02/19
Mathematics Teacher - NCLB Highly Qualified
m∠POR = 90º + (0.5)m∠PQR
115º = 90º + (0.5)m∠PQR
25º = (0.5)ºm∠PQR
50º = m∠PQR
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