How do I construct triangle DEF where EF is 3.6 cm, DE+DF is 6.4 cm and the difference of angle E and angle F is 30°?

Answer 1

ef=3.6

de+df=6.4

angle"e"-angle "f"=30

f+30=e

180-d=e+f

=2f+30

150-d=2f

Not enough information. Need sas, asa or sss.

Answer 2

Let's put this in proper labeling:

a=shortest side

b=mid

c=hypotenuse

Since 2 sides are = they are a+b; 3.2ea. c=3.6.

To get the height: a^2+b^2=c^2. In this case side c is to be cut in half=1.8.

Changing the letters: 3.2^2-1.8^2=7^.5=2.65 (height)

The area is 2.65*1.8=4.76

You're using 2 rt triangles; draw side c; mark the half way pt. Draw a rt angle up from the mark, 2.65cm. Draw sides a+b.