How many grams of C are needed to produce 1.00 × 109 g of Fe?

Question

A simplified version of the processing of iron ore into iron metal is as follows:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

How many grams of C are needed to produce 1.00 × 10⁹ g of Fe?

Answer 1

2Fe₂O₃ + 3C ==> 4Fe + 3CO₂ ... balanced equation

1.00x10⁹ g Fe x 1 mol Fe/55.85 g x 3 mol C/4 mol Fe x 12 g C/mol = 1.61x10⁸ g C