J.R. S. answered 05/02/19
Ph.D. University Professor with 10+ years Tutoring Experience
3NO2 + H2O → 2HNO3 + NO ... balanced equation
1.82x1013 g NO2 x 1 mol NO2/46.00 g = 3.957x1011 moles NO2
3.957x1011 mol NO2 x 2 mol HNO3/3 mol NO2 = 2.638x1011 moles HNO3 formed
2.638x1011 moles HNO3 x 63.01 g/mole = 1.66x1013 grams HNO3