There are 2 ways to solve this.
First
θ=arccos(1/4)=284.48
θ-45=239.48
tan(239.48)=1.696
Second
tan θ sqrt(16-1) = -sqrt(15)
tan(θ-45) = [-sqrt(15)-1]/[1-sqrt(150] = 1.696
Given that cosθ=1/4 in quadrant 4, find the tan (θ-π/4)?
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