If sin α + cos β = 2; (0° ≤ β < α ≤ 90°), then sin ((2α + β) /3)?

Answer 1

sin has a max of 1 and cos has a max of 1

therefore sina must be 1 and cosb must be 1 if sina+cosb=2

so, a=90° and b=0°

sin((2a+b)/3)=sin((180°+0°)/3)=sin(180/3)=sin60°

sin60°=(√3)/2