Terrence A. answered 12/04/14
Tutor
New to Wyzant
healthandnumbers
Pythagorean theorem: a squared+ b squared = c squared or a^2 + b ^2 = c ^2 , c is the hypotenuse, and the short leg will be x, for the sake of the problem. a, the short leg is x. b, the long leg is x+1 and c is x+9.
x^2 + (x+1)^2 = (x + 9)^2 , to solve (x+1)^2 and (x+9)^2 use FOIL (first, outside, inside , last)
x^2 + (x+1)(x+1) = (x+9)(x+9)
x^2 + (x^2 + 2x + 1) = x^2 +18x + 81
2x^2 + 2x +1 = x^2 + 18x + 81 , do some subtracting,
-2x^2 -2x -1 = - 2x^2 - 2x -1
0 = -x^2 +16x + 80, switch sides to get
x^2 - 16x-80 = 0, the numbers you would subtract to get -16 AND multiply to get -80 is -20 and 4 so,
(x-20)(x+4) = 0 , x is either 20 or -4, since -4 is impossible
x= 20 , Check your work, put 20 as the short leg, the long leg is 1 meter longer then the short so the long leg is 21, the hypotenuse is 9 meter longer the the short leg so the hypotenuse is 29
a (short leg) = 20 b (long leg) = 21 c(hypotenuse) =29 , a^2 + b ^2 = c^2
20^2 + 21^2 = 29 ^2 ,
400 + 441 = 841, which is true so the short leg is 20, the long leg is 21 and the hypotenuse is 29