Take note of the alternative hypothesis (Ha) when calculating the p-value.
In this case, the Ha: p>0.2. So the p-value = P (Z>1.40)
Use the normal Z table (or technology like TI-83 or excel) to find that this p-value ~ 0.0807566
The critical value depends on the test (in this case, it's Z) and the aalternative hypothesis. The critical value, say c, is the number c such that P(Z>c)= 0.01 (alpha). Using the normal table or some technology, this is 2.327
Since the test statistic 1.40 is not > 2.327 (and equivalently the p-value > alpha) we fail to reject the null hypothesis. No evidence to conclude that P>0.2.
