math help please q13

Question

there are 8 performers who will present their comedy acts this weekend at a comedy club one of the performers insists on being the last stand up comic of the evening if the performer's request is granted, how many different way are there to schedule the appearances?

Answer 1

7! = 5040 = 7*6*5*4*3*2*1

7 choices for 1st performance

6 choices for 2nd performance

5 choices for 3rd performance

4 choices for 4th performance

3 choices for 5th performance

2 choices for 6th performance

1 choice for 7th performance