J.R. S. answered 04/25/19
Ph.D. University Professor with 10+ years Tutoring Experience
1.50x103 amps = 1.50x103 C/sec
Assuming the plating is tri-valent chromium plating, it will be Cr3+ + 3e- ==> Cr(s) and 3 moles of electrons are needed for 1 mole of Cr(s).
150 g Cr x 1 mol/52.0 g = 2.88 moles Cr needed
2.88 moles Cr x 3 e-/mol Cr = 8.65 moles e-
8.65 moles e- x 96,485 C/mol e- = 8.3775x105 C
1.50x103C/sec (x sec) = 8.3775x105C
x = 586 sec

J.R. S.
04/25/19
Michael M.
for the final answer You mean 558.5 rounded to 559 sec? I'm not sure how you got 586?04/25/19

J.R. S.
04/25/19
Michael M.
Where did you get 68450 C/mol from?04/25/19