J.R. S. answered • 04/25/19
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80.018 g CO2 x 1 mol/44.01 g = 1.818 moles
1.818 moles x 22.4 L/mole = 40.7 liters
Andzo K.
asked • 04/25/19Chemistry - Volume CO2
Compute the volume in mL of 80.018 g carbon dioxide at STP.
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