Hello, I’m here because I need help can you please help me?

Question

calculate the amount in grams of zinc sulfate obtained by reacting 10 g of elemental zinc with 100 ml of 2m sulfuric acid

Answer 1

Zn(s) + H2SO4(aq) ==> ZnSO4(aq) + H2(g) ... balanced equation

Assuming you meant 2 M (not 2m) H2SO4, we can proceed as follows:

moles Zn = 10 g x 1 mol/65.38 g = 0.153 moles Zn

moles H2SO4 used = 0.100 L x 2 mole/L = 0.200 moles H2SO4

Which reactant is limiting? Since they appear in a 1:1 mole ratio in the balanced equation, the Zn is limiting.

Moles ZnSO4 = 0.153 moles Zn x 1 mole ZnSO4/mol Zn = 0.153 moles ZnSO4 theoretical yield

mass ZnSO4 = 0.153 moles x 161.5 g/mol = 24.7 g = 25 g ZnSO4 (to 2 significant figures)