CHEM HELP PLSS , sapling

Question

A solution contains 0.625 g of Ca2 in enough water to make a 1875 mL solution. What is the milliequivalents of Ca2 per liter (mEq/L) for this solution?

I have tried and do not understand, thank you.

Answer 1

This question involves stoichiometric conversions and the following equations will be useful:

Equivalents (Eq) = mass_{solute/compound} (g) ⁄ Gram-equivalent weight (g)

Gram-equivalent weight = Molar mass ⁄ n

You need to define the #-n for your solute — Ca++. Consider the valence/oxidation state for this cation.

Remember that the molar mass for Ca++ is ≈ 40.01 g•mol.¯¹

A simplified expression:

mEq = (mg_{solute/compound} • valence_#-n) ⁄ atomic weight (μ)

Remember that the atomic weight of calcium is ≈ 40.01 μ

Review the concepts of equivalence and gram-equivalent weight to better understand how to designate the value of n in your problem. If further help is needed to clarify on these concepts or the mathematical calculation, let me know - but try to solve the problem again with these points in mind. :)