Let m1 = mass of the ball & m2 = mass of the frisbee
Let v1 = Initial velocity the ball before impact & v2 = Initial velocity of the frisbee before impact
Let v3 = velocity of both after impact. It is assumed that the 2 objects collide and stick together after impact
(No other problem information was given otherwise!)
Then m1v1 + m2v2 = (m1 + m2)v3 inserting the information given
(.124kg)(2m/s) + (.124kg)(0m/s) = (.124 + .124)v3
.248 = .248v3
so, v3 = 1 m/s