J.R. S. answered 04/23/19
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Find mass of calcium in 1.40 g CaCO3 and then divide that by 2.13 g (x100%) to get %Ca in the pill.
1.40 g CaCO3 x 1 mole CaCO3/100.0869 g x 1 mol Ca/mole CaCO3 x 40.078 g Ca/mol Ca = 0.5606 g Ca
0.5606 g Ca/2.13 g (x100%) = 26.3% calcium in the pill