CHEMISTRY SPECIFIC HEAT HOMEWORK HELP

Question

And unknown sample is being evaluated in lab. What is the specific heat of the compound if it requires 106.47 J to raise the temperature of 58.15 grams of the unknown from 15.25 °C to 21.06 °C.?

i calculated:

106.47=(58.15g)(Specific Heat)(21.06-15.25)

i used this equation to solve for Specific Heat

I got 0.3151 but my homework tells me its wrong.

Answer 1

You did use the correct equation of q = mC∆T. Now let's check the math.

106.47 J = (58.15 g)(C)(5.81 deg)

C = 106.47 J/337.8515 g-deg

C = 0.31514 J/g/deg = 0.3151 J/g/deg (to 4 significant figurers)

So, I see nothing wrong with your answer other than omission of proper units of J/g/deg or Jg^-1deg^-1, etc.