Write an equation of the line that is perpendicular to the line y = 1/ 3 x + 6 that passes through the point (2,-3). A)y = 3x + 9 B)y = -3x - 3 C)y = -3x + 3 D)y = 1 3 x + 9 E)y = - 1 3 x + 3

Answer 1

For your line in the slope intercept form y = mx + b

y = 1/3x + 6

The slope of the Perpendicular line is the negative inverse of 1/3, so that is -3/1 or negative 3

m = -3

We can use the slope and the coordinates of the point (2, -3) to calculate b as follows:

-3 = -3(2) + b

-3 = -6 + b

Add 6 to both sides to solve for b

-3 + 6 = b

3 = b

Then we just plug our slope, m = -3 and b = 3 into slope intercept form and we have

y = mx + b

y = -3x + 3

Or choice C)y = -3x + 3

As our line perpendicular to y = 1/3x + 6

I hope this helps, give it a try and if you have any questions send me a message.