How many grams of sodium hydroxide are present in 247.0 mL of a 0.600 M NaOH solution? mass of sodium hydroxide

Answer 1

247.0 ml x 1 L/1000 ml = 0.2470 liters

0.600 moles NaOH/liter x 0.2470 liters = 0.1482 moles NaOH

0.1482 moles NaOH x 39.997 g/mole = 5.928 g NaOH = 5.93 g NaOH (to 3 significant figures)