According to the following reaction, how many moles of ammonia will be formed upon the complete reaction of 26.6 grams of nitrogen gas with excess hydrogen gas?

Question

nitrogen (g) + hydrogen (g) ammonia (g) 

Answer 1

N₂(g) + 3H₂(g) ==> 2NH₃(g) ... balanced equation

moles N₂(g) = 26.6 g x 1 mole/28 g = 0.95 moles N₂

moles NH₃ formed = 0.95 moles N₂ x 2 mole NH₃/1 mole N₂ = 1.9 moles NH₃ formed

mass NH₃ = 1.9 moles NH₃ x 17 g/mole = 32.3 g NH₃ formed