Patrick B. answered • 04/23/19
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Prob(x<62) = Prob( z < (62-65)/3.5) = Prob( z<=-0.857142) = Prob(z< -6/7) = 0.804317 or just over 80%
Amy B.
asked • 04/21/19Normala distribution
The average woman height is 65 inches with a standard deviation of 3.5 inches. What proportion of women are shorter than 62 inches tall.
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