L = length and W = width
Perimeter = 58 = 2(L + W) => L + W = 29
L = 3 + W => L - W = 3
Add the 2 equations and the W terms will add out, leaving you a value to 2L...you solve it from there.
Dazzmine A.
asked 04/20/19The perimeter is 58 meters and the length is 3 meters greater than the width. Find the length and width.
L = length and W = width
Perimeter = 58 = 2(L + W) => L + W = 29
L = 3 + W => L - W = 3
Add the 2 equations and the W terms will add out, leaving you a value to 2L...you solve it from there.
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