sin[x+(π/2)] = sin x cos π/2 + cos x sin π/2 = cos x
cos x - cos2x = 0 => cos x = 0 and 1 - cos x = 0, i.e. cos x = 1
With that information you can get the values you need.
Star L.
asked 04/20/19sin[x+(π/2)] = sin x cos π/2 + cos x sin π/2 = cos x
cos x - cos2x = 0 => cos x = 0 and 1 - cos x = 0, i.e. cos x = 1
With that information you can get the values you need.
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