
Zeeshan I. answered 04/20/19
High school/college level math and physics tutor
For a particular frequency ν, the smallest possible chunk of light (read electromagnetic radiation) called a photon has the energy
E = hν
where h is Planck's constant. So, the higher the frequency, the higher the energy of the photon.
Now, the frequency (ν), wavelength (λ) and wave speed (c) are related as
c = νλ
For light (again, read electromagnetic radiation), c is constant. Therefore we have
λ ∼ 1/ν ∼ 1/E
So, the higher the wavelength, the lower the energy of the photon.
Red light has higher wavelength (about 680 nm) than blue light (about 410 nm). Therefore red photons are less energetic than blue photons.