Bob S. answered 04/19/19
Electrical Engineer (PhD), can also help with Physics, Math and Coding
Given x^2 + y^2 = 1
In polar form
x = r*Cos(theta)
y = r*Sin(theta)
So
r^2 * Cos(theta)^2 + r^2 * Sin(theta)^2 = 1
But, since Cos()^2 + Sin()^2 = 1 we end up with
r^2 = 1
(Equation of a circle with radius = 1)