Jamara T.

asked • 04/19/19

How many grams of C3H8 are needed to react with 6.50 moles of O2

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J.R. S. answered • 04/19/19

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C3H8 + 5O2 ==> 3CO2 + 4H2O ... balanced equation

6.5 moles O2 x 1 mole C3H8/5 moles O2 x 44 g C3H8/mole C3H8 = 57.2 g C3H8 needed


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Jamara T.

can you explain what you did
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04/19/19

J.R. S.

tutor
Sure. First I wrote the balanced equation. Next, I found moles C3H8 needed to react with 6.50 moles O2 by using the mole ratio of 1:5 in the balanced equation. Then, after finding moles of C3H8, I converted that to grams of C3H8 using the molar mass of 44 g/mole. Does that make sense?
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04/19/19

Jamara T.

so you found the moles of O2 first or first C3H8
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04/19/19

J.R. S.

tutor
You don't really find the moles of O2 since that is what's given. From that you find the mole of propane
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04/19/19

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