Carolyn D.
asked 04/14/19Farris wheel modeling question
A farris wheel is 30 meters in diameter and sits on a 2 meter high platform. 6 o'clock position is is level with the platform. After 10 minutes it makes 1 complete rotation. How many minutes of the ride are spent higher than 24 meters above ground?
2 Answers By Expert Tutors
Heather P. answered 04/14/19
Certified Tutor with 19 Years Teaching & Tutoring Trig
Steven G's explanation is great for figuring out the problem algebraically/mathematically. I hope this offers an explanation of how it might look visually...
You might start by graphing the circle represented by the ferris wheel on a cartesian plane. Consider the x-axis to be the ground. The center of your circle should be (0,17), with a radius of 15. Then draw a horizontal line across your graph at y=24 and the mark its points of intersection with your circle as A & B. Now, consider that the ferris wheel is a clock whose hands rotate every 10 min instead of 60 min. How many minutes are there between A & B, above the line y=24?
I hope this helps. Please let us know if you need further assistance.
Assume that the center, C, of wheel is on the ground and the problem ask for how many minutes are you 7 m above the ground.
The equation of the wheel is x^2+y^2 = 15^2 = 225
Find where this wheel (circle) intersects the line y=7. This will give you two points, say A and B. Now draw lines AC and BC. Find the measure of the angle ACB, call this value t radians
Then the answer will be 10*( t/(2pi))
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Carolyn D.
I'm sorry. But I'm still very confused got an equation. D(t)=-15cos(pi/5t)+17 And i put 24 meters in for t and got 3.2727. And i got 8.27 as its inverse. But its wrong. So im stuck04/15/19