Carolyn D.
asked 04/14/19Farris wheel modeling question
A farris wheel is 30 meters in diameter and sits on a 2 meter high platform. 6 o'clock position is is level with the platform. After 10 minutes it makes 1 complete rotation. How many minutes of the ride are spent higher than 24 meters above ground?
2 Answers By Expert Tutors
Inactive Tutor answered 04/14/19
Steven G's explanation is great for figuring out the problem algebraically/mathematically. I hope this offers an explanation of how it might look visually...
You might start by graphing the circle represented by the ferris wheel on a cartesian plane. Consider the x-axis to be the ground. The center of your circle should be (0,17), with a radius of 15. Then draw a horizontal line across your graph at y=24 and the mark its points of intersection with your circle as A & B. Now, consider that the ferris wheel is a clock whose hands rotate every 10 min instead of 60 min. How many minutes are there between A & B, above the line y=24?
I hope this helps. Please let us know if you need further assistance.
Inactive Tutor answered 04/14/19
Assume that the center, C, of wheel is on the ground and the problem ask for how many minutes are you 7 m above the ground.
The equation of the wheel is x^2+y^2 = 15^2 = 225
Find where this wheel (circle) intersects the line y=7. This will give you two points, say A and B. Now draw lines AC and BC. Find the measure of the angle ACB, call this value t radians
Then the answer will be 10*( t/(2pi))
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Carolyn D.
I'm sorry. But I'm still very confused got an equation. D(t)=-15cos(pi/5t)+17 And i put 24 meters in for t and got 3.2727. And i got 8.27 as its inverse. But its wrong. So im stuck04/15/19