J.R. S. answered 04/14/19
Ph.D. University Professor with 10+ years Tutoring Experience
MCO3 + 2H+ ===> M2+ + CO2 + H2O balanced equation
Since the molar mass of CO2 is 44 g/mole, find a metal carbonate where 44/molar mass = 0.30.
So, 44/x = 0.3 and x = 147 g/mol as a molar mass of the metal carbonate.
Since CO32- has a molar mass of 60, the metal would have an atomic mass of 147 - 60 = 87.
This would be strontium (Sr2+) Choice (b)
To check this out, look at SrCO3
Sr = 87
C = 12
O = 16 x 3 = 48
Molar mass = 147 g/mole
If you had 100 g of SrCO3, you'd have 0.68 mole
1 mole SrCO3 produces 1 mole CO2 so there's be 0.68 mole CO2
0.68 mol CO2 x 44 g/mole = 29.9 g CO2
29.9 g CO2/100 g SrCO3 = 29.9% CO2 (close enough)