J.R. S. answered 04/14/19
Ph.D. University Professor with 10+ years Tutoring Experience
2Na3PO4(aq) + 3Co(NO3)2(aq) ==> Co3(PO4)2(s) + 6NaNO3(aq)
moles Na3PO4 present = 0.060 L x 0.0890 mol/L = 0.00534 moles
moles Co(NO3)2 needed = 0.00534 mol Na3PO4 x 3 mol Co(NO3)2 / 2 mol Na3PO4 = 0.00801 mol Co(NO3)2
mass of Co(NO3)2 needed = 0.00801 moles x 182.94 g/mol = 1.47 g (to 3 significant figures)