J.R. S. answered • 04/13/19
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What is H^4IO^-6 supposed to be? Perhaps it's supposed to be tetrahydrogen orthoperiodate which is
H4IO6-. Given that to be the case the oxidate state of I would be 7+
J.R. S.
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To get the ox. no. of I, you add up the known ox. numbers and include the charge of -1 on the ion. So, there are 6 O atoms, each with a 2- ox. no. (that's 12-). Then, there are 4 H atoms, each with a 1+ ox. no. (that's 4+). So -12 and +4 leaves = -8. But the charge on the ion is -1, so the I MUST be 7+.
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