oxalate analysis (synthesis)

Question

A 1.20 g sample of a compound congtaining oxalate was titrated with 27.40 ml of a 0.0450 M solution of KMnO4.

a.)How many moles of KMnO4 were used in the titration?

b.)How many moles of oxalate were present in the reaction?

c.)How many grams of oxalate were present in the reaction?

d.)What percent of the unknown compound is oxalate?

Answer 1

This is very similar to a question you asked previously. You should look at that and see if you can't answer this question.

HINT: 2MnO₄^- + 16H⁺ + 5C₂O₄^2- ===> 2Mn²⁺ + 8H₂O + 10CO₂ (use this balanced equation)

a) 0.0274 L x 0.0450 mol/L = moles KMnO₄ used

b) use the stoichiometry of 5 moles oxalate to 2 moles KMnO₄

c) convert moles oxalate to grams oxalate

d) divide g oxalate by 1.20 g and multiply by 100%