How much energy (in J) is lost when a sample of iron with a mass of 26.8 g cools from 71.0 ∘C to 22.0 ∘C?

Question

How much energy (in J) is lost when a sample of iron with a mass of 26.8 g cools from 71.0 ∘C to 22.0 ∘C?

Answer 1

q = mC∆T

q = mass = 26.8 g

C = specific heat of iron = 0.46 J/g/deg (look it up or use the value provided to you)

T = change in temperature = 71.0 - 22.0 = 49 degrees

q = (26.8 g)(0.46 J/g/deg)(49 deg) = 604 joules of energy is lost during the cooling.