Please help me with this

Question

ABC is isosceles. Ab= 3x-4 and Bc=5x-10.

Answer 1

An isosceles triangle is a triangle in which two of the sides have equal length. We are given that in triangle ABC, the side AB has length 3x-4 and the side BC has length 5x-10. We will assume these are the two equal sides of the triangle. So since they are equal we get the equation

3x-4 = 5x-10

which we must solve for x. We begin by adding 10 to both sides of the equation to get

3x-4+10 = 5x-10+10

3x+6 = 5x

now we subtract 3x from both sides to get

3x+6-3x = 5x-3x

6 = 2x.

Finally we should divide both sides by 2 to get

6/2 = 2x/2

3 = x

and so we get our final answer x=3.

Answer 2

You must find a way to relate the angles ABC and ACB (the base angles). The problem states the triangle is isosceles (which technically means the triangle has two sides of the same length). Because the triangle is isosceles, the angles formed by the base angles are equal.

So Ab= Bc

3x-4=5x-10

(...bit of algebra)

2x=6

x=3