J.R. S. answered 04/08/19
Ph.D. University Professor with 10+ years Tutoring Experience
2HNO3 (aq)+Ba(OH)2 (aq)------>2H2O(l)+Ba(NO3)2(aq).
moles Ba(OH)2 used = 0.0419 L x 0.150 mol/L = 0.006285 moles
Now find moles of HNO3:
0.006285 mole Ba(OH)2 x 2 mole HNO3/mol Ba(OH)2 = 0.01257 moles HNO3
Concentration of HNO3 = 0.01257 moles/0.115 L = 0.109 M (to 3 significant figures)