J.R. S. answered 04/07/19
Ph.D. University Professor with 10+ years Tutoring Experience
Ag2CrO4(s) ===> 2Ag+(aq) + CrO42+(aq)
Ksp = 9x10-12 = [Ag+]2[CrO42-]
9x10-12 = (x)2(0.002)
x2 = 4.5x10-9
x = 6.5x10-5 M = [Ag+]
doyin o.
asked 04/07/19If a solution contains 0.0020 mol of CrO2−4 per liter and solid AgNO3 is added, what concentration of Ag+ ion must be reached to cause Ag2CrO4 to begin to precipitate? For Ag2CrO4, Ksp=9.0×10−12.
J.R. S. answered 04/07/19
Ph.D. University Professor with 10+ years Tutoring Experience
Ag2CrO4(s) ===> 2Ag+(aq) + CrO42+(aq)
Ksp = 9x10-12 = [Ag+]2[CrO42-]
9x10-12 = (x)2(0.002)
x2 = 4.5x10-9
x = 6.5x10-5 M = [Ag+]
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Caroline B.
for knewton.com the answer is 6.7X10^-510/14/20