When you circumscribe a quadrilateral around a circle, the sums of the opposite sides of the quadrilateral are equal. So:
CD + AB = AD + BC
10 + 5 = 8 + BC
Solve for BC.
Jessica K.
asked 04/06/19When you circumscribe a quadrilateral around a circle, the sums of the opposite sides of the quadrilateral are equal. So:
CD + AB = AD + BC
10 + 5 = 8 + BC
Solve for BC.
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