
Tamara J. answered 03/12/13
Math Tutoring - Algebra and Calculus (all levels)
You made an typing error when you were posting the problem, but I think the problem you are looking to solve for is as follows: x2 + 10x + 25 = 16
Note that we need to factor the left hand side of the equation in such a way that we get a product of two identical binomials (i.e., a perfect square).
Recall that to complete the square we use the following formula: (b/2)2
In this problem b=10, so (b/2)2 = (10/2)2 = (5)2
This tells us that the left hand side of the original equation factors into (x + 5)2. That is,
x2 + 10x + 25 = 16
(x + 5)(x + 5) = 16
(x + 5)2 = 16
Now, take the square root of both sides of the equation:
√(x + 5)2 = √16
(x + 5) = ± 4
x + 5 = ± 4
Subtract 5 from both sides of the equation to solve for x:
x + 5 = ± 4
- 5 - 5
______________
x = -5 ± 4 ==> x = -5 + 4 and x = -5 - 4
x = -5 + 4 = -1
x = -5 - 4 = -9
Thus, x = -1 and x = -9