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Question

How many liters of a 3.06 M K2SO4 solution are needed to provide 61.8 g of K2SO4(molar mass 174.01 g/mol)?

Answer 1

61.8 g K2SO4 x 1 mole/174.01 g = 0.355 moles of K2SO4

(x L)(3.06 mol/L) = 0.355 moles

x = 0.116 Liters

Answer 2

x ml of 3.06 M K₂SO₄ gives 61.8 g of K₂SO₄

(M)*(1)*(M.W) * Vol = (3.06 mol/L)*(1 L/1000 ml)*(174.01 g K₂SO₄/mol) * Vol (ml) = 61.8 g K₂SO₄

Solve for Vol (ml).

Vol (ml) = (61.8 g K₂SO₄)/((3.06 mol/L)*(1 L/1000 ml)*(174.01 g K₂SO₄/mol))

Vol (ml) = (61.8 /3.06*1000/174.01) ml = 116 ml