what is the point-slope form of a line with slope -3 that contains the point (10,-1)

Answer 1

(y + 1) = -3(x - 10)

Answer 2

Point Slope Form

Point slope form = y - y₁ = m(x- x₁)

where

(x₁, y₁) are the point on the line, m = Slope of the line

For a line containing point (10,-1) having a slope of (-3), this is:

y - (-1) = (-3)(x-10) [this is the point-slope form of the equation of the line]

y + 1 = -3x + 10 [it is usually o.k. to write the point-slope form this way -- do only slight simplification; do not move terms]

Additional information:

y = -4x + 10 [this is the slope-intercept form of the equation of the line]

4x + y = 10 [this is the Standard Form of the equation of the line]

4x + y -`0 = 0 [this is the General Form of the equation of the line]

. . . [there are more]

Answer 3

y - y1 = m (x - x1)

y - (-1) = -3 (x - 10)

y + 1 = -3 (x - 10) is the Point-Slope form.