balance using the half reaction method?

Question

Question 7 options:

Answer the following questions and balance the equation below using the half-reaction method

AgOCN_(aq) + Co_(s) → Co(OH)_2(s) + Ag_(s) + OCN⁻_(aq)

To balance the number of electrons, the reduction half-reaction must be multiplied by?  

The final balanced equation is?

Answer 1

AgOCN(aq) + e- ===> Ag(s) + OCN-(aq) reduction half-reaction

Co(s) + 2OH- ===> Co(OH)2(s) + 2e- oxidation half-reaction

To balance the number of electrons (2e-), the reduction half-reaction must be multiplied by 2

The final balanced equation is 2AgOCN(aq) + Co(s) + 2OH^-(aq) ==> 2Ag(s) + 2OCN^-(aq) + Co(OH)2(s)