Mark M. answered 04/03/19
Mathematics Teacher - NCLB Highly Qualified
Thee consecutive integers:
n, n + 1, and n + 2
n(n+1) = 5(n + 2) - 5
Can you solve for n and answer?
Mark M. answered 04/03/19
Mathematics Teacher - NCLB Highly Qualified
Thee consecutive integers:
n, n + 1, and n + 2
n(n+1) = 5(n + 2) - 5
Can you solve for n and answer?
Timothy A. answered 04/03/19
I am here to raise mathematicians.
Integer 1 = x
Integer 2 = x+1
Integer 3 = x+2
x(x+1)= 5(x+2) - 5
x^2 + x = 5x + 10 - 5
x^2 -4x - 5 = 0
(x+1)(x-5) = 0
x = -1 or 5
If we want the smallest integers
Integer 1 = x = -1
Integer 2 = x+1 = 0
Integer 3 = x+2 = 1
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