what is the value of the positive zero of the function defined by (x-3)^2-16?

Question

What is the value of the positive zero of the function defined by (x - 3)² - 16?

Answer 1

(x-3)(x-3)-16

Foil to get

x²-6x+9-16

x²-6x-7=0

Factor

(X-7)(x+1)=0

Set each equal to zero

X-7=0. So x=7

X+1=0 so x=-1

The positive zero is 7