J.R. S. answered 04/01/19
Ph.D. University Professor with 10+ years Tutoring Experience
Determine Ccal (specific heat of the calorimeter):
7.62 g CH4 x 1mole CH4/16.0 g = 0.4763 mole
0.4763 mole x 902 kJ/mol = 430 kJ
430 kJ/42.2ºC = 10.2 kJ/degree
For combustion of octane:
14.6 degrees x 10.2 kJ/degree = 149 kJ
3.10 g x 1 mol/114 g = 0.0272 moles octane
∆Ecomb = 149 kJ/0.0272 moles = -5478 kJ/mole